2x^2-30x-32=0

Solution for 2x^2-30x-32=0 equation:

2x^2-30x-32=0

a = 2; b = -30; c = -32;
Δ = b2-4ac
Δ = -302-4·2·(-32)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1156}=34$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-34}{2*2}=\frac{-4}{4}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+34}{2*2}=\frac{64}{4}
=16
$